위수가 30 이하인 유한군의 분류

작성자폭풍속으로|작성시간05.11.17|조회수1,575 목록 댓글 2

Groups of small order

Compiled by John Pedersen, Dept of Mathematics, University of South Florida, jfp@math.usf.edu


Order 1 and all prime orders (1 group: 1 abelian, 0 nonabelian)

All groups of prime order p are isomorphic to C_p, the cyclic group of order p.
A concrete realization of this group is Z_p, the integers under addition modulo p.

Order 4 (2 groups: 2 abelian, 0 nonabelian)

  • C_4, the cyclic group of order 4
  • V = C_2 x C_2 (the Klein four group) = symmetries of a rectangle. A presentation for the group is
                <a, b; a^2 = b^2 = (ab)^2 = 1> 
    The Cayley table of the group is (putting c = ab):
                  | 1  a  b  c
                --+-----------
                1 | 1  a  b  c
                a | a  1  c  b
                b | b  c  1  a
                c | c  b  a  1 
    A matrix representation is the four 2x2 matrices
                [1 0]   [1  0]   [-1 0]   [-1  0]
                [0 1],  [0 -1],  [ 0 1],  [ 0 -1] 
    A permutation representation is the following four elements of S_4:
               (1),  (1 2)(3 4),  (1 3)(2 4) and (1 4)(2 3).  
    Its lattice of subgroups is (in the notation of the Cayley table)
                          V
                       /  |  \
                     <a> <b> <c>
                       \  |  /
                         {1} 

Order 6 (2 groups: 1 abelian, 1 nonabelian)

  • C_6
  • S_3, the symmetric group of degree 3 = all permutations on three objects, under composition. In cycle notation for permutations, its elements are (1), (1 2), (1 3), (2, 3), (1 2 3) and (1 3 2).
    There are four proper subgroups of S_3; they are all cyclic. There are the three of order 2 generated by (1 2), (1 3) and (2 3), and the one of order 3 generated by (1 2 3). Only the one of order 3 is normal in S_3.
    A presentation for S_3 is (where s corresponds to (1 2) and t to (2 3)):
                <s,t; s^2 = t^2 = 1, sts = tst> 
    Another presentation (with s <-> (1 2 3), t <-> (1 2)) is
                <s,t; s^3 = t^2 = 1, ts = s^2 t> 
    In terms of this second presentation, with 2 = s^2, u = ts and v = ts^2, the Cayley table is
                  | 1  s  2  t  u  v
                --+-----------------------
                1 | 1  s  2  t  u  v
                s | s  2  1  v  t  u
                2 | 2  1  s  u  v  t
                t | t  u  v  1  s  2
                u | u  v  t  2  1  s
                v | v  t  u  s  2  1 
    This shows S_3 is isomorphic to D_3, the dihedral group of degree 3, that is, the symmetries of an equilateral triangle (this never happens for n > 3). The lattice of subgroups of S_3 is
                              S_3
                        /  /   |   \
                      <t> <u> <v>  <s>
                        \  \   |   /
                              {1} 
    The first three proper subgroups have order two, while <s> has order three and is the only normal one.
    The center of S_3 is trivial (in fact Z(S_n) is trivial for all n.)
    The automorphism group of S_3 is isomorphic to S_3.

Order 8 (5 groups: 3 abelian, 2 nonabelian)

  • C_8
  • C_4 x C_2
  • C_2 x C_2 x C_2
  • D_4, the dihedral group of degree 4, or octic group. It has a presentation
                 <s, t; s^4 = t^2 = e; ts = s^3 t> 
    In terms of these generators (s corresponds to rotation by pi/2 and t to a reflection about an axis through a vertex), the eight elements are 1,s,s^2,s^3,t,ts,ts^2 and ts^3. Using the notation 2 = s^2, 3 = s^3, t2 = ts^2 and t3 = ts^3, the Cayley table is
                  | 1  s  2  3  t ts t2 t3
                --+------------------------
                1 | 1  s  2  3  t ts t2 t3
                s | s  2  3  1 t3  t ts t2
                2 | 2  3  1  s t2 t3  t ts
                3 | 3  1  s  2 ts t2 t3  t
                t | t ts t2 t3  1  s  2  3
               ts |ts t2 t3  t  3  1  s  2
               t2 |t2 t3  t ts  2  3  1  s
               t3 |t3  t ts t2  s  2  3  1 
    Its subgroup lattice is
                                 D_4
                      /           |         \
               {1,s^2,t,ts^2}    <s>   {1,s^2,st,ts}
             /     |         \    |   /       |      \
         <ts^2>   <t>           <s^2>       <st>     <ts>
              \      \            |          /        /
                                 {1} 
    Of these, the proper normal subgroups are the three of order four and <s^2> of order two.
    The center of D_4 is {1,s^2}, which is also its derived group.
    The automorphism group of D_4 is isomorphic to D_4.

  • Q, the quaternion group. It has a presentation
                 <s, t; s^4 = 1, s^2 = t^2, sts = t> 
    Q can be realized as consisting of the eight quaternions 1, -1, i, -i, j, -j, k, -k, where i is the imaginary square root of -1, and j and k also obey j^2 = k^2 = -1. These quaternions multiply according to clockwise movement around the figure
                                   i
                                /      \
                               k  ----  j 
    For example, ij = k and ji = -k (negative because anticlockwise).
    A matrix representation is given by s and t in the above presentation corresponding to these two 2x2 matrices over the complex numbers:
               s = [i  0]     t = [0 i]
                   [0 -i]         [i 0] 
    The subgroup lattice of Q is
                                      Q
                                /     |     \
                              <s>    <st>   <t>
                                \     |     /
                                    <s^2>
                                      |
                                     {1} 
    All of these subgroups are normal in Q.
    The center of Q is {1,s^2}, which is also its derived group.
    The automorphism group of Q is isomorphic to S_4.

Order 9 (2 groups: 2 abelian, 0 nonabelian)

  • C_9
  • C_3 x C_3

Order 10 (2 groups: 1 abelian, 1 nonabelian)

  • C_10
  • D_5

Order 12 (5 groups: 2 abelian, 3 nonabelian)

  • C_12
  • C_6 x C_2
  • A_4, the alternating group of degree 4, consisting of the even permutations in S_4. The subgroup lattice of A_4 is
                                   A_4
                                /     \        \        \         \
              <(12)(34),(13)(24)>    <(123)>  <(124)>  <(134)>  <(234)>
               /       |       \         |       /       /         /
        <(12)(34)> <(13)(24)> <(14)(23)> |      /       /         /
               \       \          \      /     /       /         /
                                     {1} 
    The only proper normal subgroup is <(12)(34),(13)(24)>.
  • D_6, isomorphic to S_3 x C_2 = D_3 x C_2
  • T which has the presentation
           <s, t; s^6 = 1, s^3 = t^2, sts = t> 
    T is the semidirect product of C_3 by C_4 by the map g : C_4 -> Aut(C_3) given by g(k) = a^k, where a is the automorphism a(x) = -x.
    Another presentation for T is
            <x,y; x^4 = y^3 = 1, yxy = x> 
    In terms of these generators, using AB for x^A y^B, the Cayley table for T is
               | 00  10  20  30  01  02  11  21  31  12  22  32
         ------+-----------------------------------------------
         1 = 00| 00  10  20  30  01  02  11  21  31  12  22  32
         x = 10| 10  20  30  00  11  12  21  31  01  22  32  02
       x^2 = 20| 20  30  00  10  21  22  31  01  11  32  02  12
       x^3 = 30| 30  00  10  20  31  32  01  11  21  02  12  22
         y = 01| 01  12  21  32  02  00  10  22  30  11  20  31
       y^2 = 02| 02  11  22  31  00  01  12  20  32  10  21  30
        xy = 11| 11  22  31  02  12  10  20  32  00  21  30  01
      x^2y = 21| 21  32  01  12  22  20  30  02  10  31  00  11
      x^3y = 31| 31  02  11  22  32  30  00  12  20  01  10  21
      xy^2 = 12| 12  21  32  01  10  11  22  30  02  20  31  00
    x^2y^2 = 22| 22  31  02  11  20  21  32  00  12  30  01  10
    x^3y^2 = 32| 32  01  12  21  30  31  02  10  22  00  11  20 
    A 2x2 matrix representation of this group over the complex numbers is given by
                       [0  i]              [w   0 ]
                x <--> [i  0]       y <--> [0  w^2]  
    where i is a square root of -1 and w is nonreal cube root of 1, for example w = e^{2\pi i/3}.

Order 14 (2 groups: 1 abelian, 1 nonabelian)

  • C_14
  • D_7

Order 15 (1 group: 1 abelian, 0 nonabelian)

C_15.

Order 16 (14 groups: 5 abelian, 9 nonabelian)

  • C_16
  • C_8 x C_2
  • C_4 x C_4
  • C_4 x C_2 x C_2
  • C_2 x C_2 x C_2 x C_2
  • D_8
  • D_4 x C_2
  • Q x C_2, where Q is the quaternion group
  • The quasihedral (or semihedral) group of order 16, with presentation
            <s,t; s^8 = t^2 = 1, st = ts^3> 
  • The modular group of order 16, with presentation
            <s,t; s^8 = t^2 = 1, st = ts^5> 
    The elements are s^k t^m, k = 0,1,...,7, m = 0,1.
    The center is {1,s^2,s^4,s^6}.
    Its subgroup lattice is
                                 G
                             /   |   \
                       <s^2,t>  <s>  <st>
                      /   |   \  |   /
                <s^4,t> <s^2t>  <s^2>
                /  |   \  |     /
             <t> <s^4t>  <s^4>
                \  |    /
                  {1}            
    This is the same subgroup lattice structure as for the lattice of subgroups of C_8 x C_2, although the groups are of course nonisomorphic.
    The automorphism group is isomorphic to D_4 x C_2
    Reference: Weinstein, Examples of Groups, pp. 120-123.
  • The group with presentation
               < s,t; s^4 = t^4 = 1, st = ts^3 >  
    The elements are s^i t^j for i,j = 0,1,2,3.
    The center of G is {1,s^2,t^2,s^2t^2}.
    Reference: Weinstein, pp. 124--128.
  • The group with presentation
      <a,b,c; a^4 = b^2 = c^2 = 1, cbca^2b = 1, bab = a, cac = a> 
  • The group G_{4,4} with presentation
    <s,t; s^4 = t^4 = 1, stst = 1, ts^3 = st^3 > 
    
    
  • The generalized quaternion group of order 16 with presentation
    <s,t; s^8 = 1, s^4 = t^2, sts = t > 

Order 18 (5 groups: 2 abelian, 3 nonabelian)

  • C_18
  • C_6 x C_3
  • D_9
  • S_3 x C_3
  • The semidirect product of C_3 x C_3 with C_2 which has the presentation
        <x,y,z; x^2 = y^3 = z^3 = 1, yz = zy, yxy = x, zxz = x> 

Order 20 (5 groups: 2 abelian, 3 nonabelian)

  • C_20
  • C_10 x C_2
  • D_10
  • The semidirect product of C_5 by C_4 which has the presentation
           <s,t; s^4 = t^5 = 1, tst = s> 
  • The Frobenius group of order 20, with presentation
           <s,t; s^4 = t^5 = 1, ts = st^2> 
         
    This is the Galois group of x^5 -2 over the rationals, and can be represented as the subgroup of S_5 generated by (2 3 5 4) and (1 2 3 4 5).

Order 21 (2 groups: 1 abelian, 1 nonabelian)

  • C_21
  • <a,b; a^3 = b^7 = 1, ba = ab^2> This is the Frobenius group of order 21, which can be represented as the subgroup of S_7 generated by (2 3 5)(4 7 6) and (1 2 3 4 5 6 7), and is the Galois group of x^7 - 14x^5 + 56x^3 -56x + 22 over the rationals (ref: Dummit & Foote, p.557).

Order 22 (2 groups: 1 abelian, 1 nonabelian)

  • C_22
  • D_11

Order 24 (15 groups: 3 abelian, 12 nonabelian)

  • C_24
  • C_2 x C_12
  • C_2 x C_2 x C_6
  • S_4
  • S_3 x C_4
  • S_3 x C_2 x C_2
  • D_4 x C_3
  • Q x C_3
  • A_4 x C_2
  • T x C_2
  • Five more nonabelian groups of order 24
    Reference: Burnside, pp. 157--161.

Order 25 (2 groups: 2 abelian, 0 nonabelian)

  • C_25
  • C_5 x C_5

Order 26 (2 groups: 1 abelian, 1 nonabelian)

  • C_26
  • D_13

Order 27 (5 groups: 3 abelian, 2 nonabelian)

  • C_27
  • C_9 x C_3
  • C_3 x C_3 x C_3
  • The group with presentation
            <s,t; s^9 = t^3 = 1, st = ts^4 > 
  • The group with presentation
      <x,y,z; x^3 = y^3 = z^3 = 1, yz = zyx, xy = yx, xz = zx> 
    Reference: Burnside, p. 145.

Order 28 (4 groups: 2 abelian, 2 nonabelian)

  • C_28
  • C_2 x C_14
  • D_14
  • D_7 x C_2

Order 30 (4 groups: 1 abelian, 3 nonabelian)

  • C_30
  • D_15
  • D_5 x C_3
  • D_3 x C_5
    Reference: Dummit & Foote, pp. 183-184.

A Catalogue of Algebraic Systems / John Pedersen / jfp@math.usf.edu
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  • 작성자체 게바라 | 작성시간 05.11.18 여기서 C_n 이란 위수 n 인 순환군을 가르키는 것이겠군요??? Zn으로 써도 무난할까요???
  • 답댓글 작성자폭풍속으로 작성자 본인 여부 작성자 | 작성시간 05.11.18 맞습니다. C_n 은 위수가 n 인 순환군을 말합니다. 동형에 관계없이 위수가 n 인 부분군은 Z_n 으로 유일하므로 Z_n 으로 써도 무방합니다. 책에 따라서는 Z_n 보다는 C_n 으로 쓰는 경우가 있기도 합니다. 참고로, C_n = { e, x, x^2, x^3, ... , x^(n-1) } 로 나타냅니다. 경문사 현대대수학 교재에 소개되어 있습니다.
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